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Syllabus

This is based on the IB Mathematics: Analysis and Approaches syllabus (first assessment 2021).

The IB Mathematics AA syllabus is structured like a journey from concrete to abstract. Number and Algebra provides the computational foundation. Functions introduce the idea of transformation and mapping. Trigonometry extends algebra into circular and periodic phenomena. Calculus reveals how to measure change and accumulation. Statistics and Probability quantify uncertainty. Vectors and Matrices describe spatial relationships and linear transformations. The syllabus mirrors how mathematical thought evolved historically, from solving practical problems to abstract reasoning.

TopicSubtopicLevelKey UnderstandingRelevant Equations & Identities
1. Number and AlgebraArithmetic SequencesSL & HLSequences with a constant common difference; finding the nth term and the sum of the first n terms.u_n = u_1 + (n-1)d
Arithmetic SeriesSL & HLSum formulae for arithmetic series in terms of first term, last term, common difference, and number of terms.S_n = (n/2)(2u_1 + (n-1)d) = (n/2)(u_1 + u_n)
Geometric SequencesSL & HLSequences with a constant common ratio; finding the nth term.u_n = u_1 r^{n-1}
Geometric SeriesSL & HLFinite and infinite geometric series; convergence conditions for infinite series.S_n = u_1(1 - r^n)/(1 - r); S_inf = u_1/(1 - r) for `
Sigma NotationSL & HLUsing summation notation to express and evaluate series; rules for manipulating sums.\sum_{r=1}^n u_r; \sum_{r=1}^n k = kn; \sum_{r=1}^n (a_r + b_r) = \sum a_r + \sum b_r
The Binomial TheoremSL & HLExpansion of (a + b)^n using binomial coefficients; Pascal’s triangle and the relationship to combinations.(a+b)^n = \sum_{r=0}^n \binom{n}{r} a^{n-r} b^r; \binom{n}{r} = n! / (r!(n-r)!)
Applications of the Binomial TheoremSL & HLFinding specific terms in a binomial expansion without fully expanding.General term: T_{r+1} = \binom{n}{r} a^{n-r} b^r
Compound InterestSL & HLCalculating the future value of an investment or loan with compounding.FV = PV(1 + r)^n where r is the rate per period and n is the number of periods
Compound DepreciationSL & HLCalculating the depreciated value of an asset over time.FV = PV(1 - r)^n
PermutationsHL OnlyCounting ordered arrangements of objects; counting with and without repetition.^nP_r = n!/(n-r)!
CombinationsHL OnlyCounting unordered selections; applications to probability and combinatorial problems.^nC_r = n!/(r!(n-r)!)
Complex Numbers: IntroductionHL OnlyThe imaginary unit i where i^2 = -1; complex numbers in Cartesian form a + bi.z = a + bi; i^2 = -1; i^3 = -i; i^4 = 1
Complex Numbers: OperationsHL OnlyAddition, subtraction, multiplication, and division of complex numbers; equating real and imaginary parts.(a+bi)(c+di) = (ac-bd) + (ad+bc)i; division by multiplying by the conjugate
Modulus of a Complex NumberHL OnlyThe modulus is the distance from the origin to the point (a, b) on the Argand diagram.`
Argument of a Complex NumberHL OnlyThe argument is the angle from the positive real axis to the line joining the origin to the point (a, b).\arg(z) = \arctan(b/a) with quadrant adjustment; principal argument -\pi < \theta \le \pi
Polar FormHL OnlyRepresenting complex numbers in modulus-argument (polar) form on the Argand diagram.z = r(\cos\theta + i\sin\theta) = r\,\mathrm{cis}\,\theta
Euler FormHL OnlyEuler’s formula and the exponential representation of complex numbers.e^{i\theta} = \cos\theta + i\sin\theta; z = re^{i\theta}; e^{i\pi} + 1 = 0
De Moivre’s TheoremHL OnlyRaising complex numbers to integer powers using polar form.[r(\cos\theta + i\sin\theta)]^n = r^n(\cos n\theta + i\sin n\theta)
Roots of Complex NumbersHL OnlyFinding the nth roots of a complex number; roots lie equally spaced on a circle of radius r^{1/n}.z_k = r^{1/n}[\cos((\theta + 2k\pi)/n) + i\sin((\theta + 2k\pi)/n)] for k = 0, 1, \ldots, n-1
Complex Conjugate Root TheoremHL OnlyIf a polynomial with real coefficients has a complex root a + biThen a - bi is also a root.If f(a+bi) = 0 then f(a-bi) = 0 for real coefficients
Sum and Product of RootsHL OnlyRelationship between coefficients and sums/products of roots for polynomial equations.Quadratic: sum = -b/aProduct = c/a; Cubic: sum = -b/aSum of pairwise = c/aProduct = -d/a
Proof by ContradictionHL OnlyAssuming the negation of a statement and arriving at a contradiction to prove the original statement.N/A
Proof by Mathematical InductionHL OnlyProving statements for all positive integers using the induction principle: base case, inductive hypothesis, inductive step.N/A
CounterexamplesHL OnlyUsing a single counterexample to disprove a universal statement.N/A
Direct VariationHL OnlyModelling directly proportional relationships between two variables.y = kx; y_1/x_1 = y_2/x_2
Inverse VariationHL OnlyModelling inversely proportional relationships between two variables.y = k/x; x_1 y_1 = x_2 y_2
2. FunctionsLinear FunctionsSL & HLEquations and graphs of straight lines; gradient, intercepts, parallel and perpendicular lines.y = mx + c; m = (y_2 - y_1)/(x_2 - x_1); perpendicular gradients: m_1 m_2 = -1
Quadratic Functions: Standard FormSL & HLf(x) = ax^2 + bx + c; identifying the y-intercept and direction of opening.y-intercept at (0, c); opens up if a > 0Down if a < 0
Quadratic Functions: Vertex FormSL & HLf(x) = a(x - h)^2 + k; identifying the vertex, axis of symmetry, and optimal value.Vertex at (h, k); axis of symmetry x = h
Quadratic Functions: DiscriminantSL & HLThe discriminant determines the number and nature of roots.D = b^2 - 4ac; D > 0: two distinct real roots; D = 0: one repeated root; D < 0: no real roots
Exponential FunctionsSL & HLProperties and graphs; exponential growth and decay; the natural exponential function e^x.y = a^x; y = e^x; horizontal asymptote at y = 0
Logarithmic FunctionsSL & HLDefinition as the inverse of exponentiation; domain and range; graphs of \log_a x.y = \log_a x iff a^y = x; domain x > 0; passes through (1, 0)
Laws of LogarithmsSL & HLProduct, quotient, and power rules for logarithms; change of base formula.\log_a(xy) = \log_a x + \log_a y; \log_a(x/y) = \log_a x - \log_a y; \log_a(x^n) = n\log_a x
Solving EquationsSL & HLSolving equations analytically and graphically; intersection of graphs as solutions to f(x) = g(x).N/A
Domain and RangeSL & HLIdentifying the domain (set of inputs) and range (set of outputs) of functions from their equations and graphs.N/A
Even and Odd FunctionsSL & HLSymmetry properties: even functions are symmetric about the y-axis; odd functions have rotational symmetry about the origin.Even: f(-x) = f(x); Odd: f(-x) = -f(x)
Horizontal TranslationsSL & HLShifting graphs left or right by a constant.y = f(x - b) shifts right by b units; y = f(x + b) shifts left by b units
Vertical TranslationsSL & HLShifting graphs up or down by a constant.y = f(x) + c shifts up by c units; y = f(x) - c shifts down by c units
ReflectionsSL & HLReflecting graphs in the x-axis, y-axis, and the line y = x.y = -f(x) (x-axis); y = f(-x) (y-axis); y = f^{-1}(x) (line y = x)
StretchesSL & HLVertical and horizontal stretches and compressions of graphs.y = af(x) (vertical stretch by factor a); y = f(bx) (horizontal stretch by factor 1/b)
Composite FunctionsSL & HLCombining two or more functions; finding the domain of a composite function.(f \circ g)(x) = f(g(x)); domain of f \circ g is the set of x in domain of g where g(x) is in domain of f
Inverse FunctionsSL & HLFinding the inverse function algebraically; reflecting the graph of f in y = x to obtain f^{-1}.f^{-1}(f(x)) = x; domain of f^{-1} = range of f; range of f^{-1} = domain of f
Polynomial FunctionsSL & HLIdentifying polynomials by degree; determining end behaviour, intercepts, and turning points; sketching graphs.f(x) = a_n x^n + a_{n-1} x^{n-1} + \cdots + a_1 x + a_0
Linear InequalitiesSL & HLSolving and representing solutions to linear inequalities on a number line.ax + b > 0; multiply/divide by negative reverses the inequality
Quadratic InequalitiesSL & HLSolving quadratic inequalities using the discriminant and sign analysis.Sign analysis of (x - \alpha)(x - \beta) > 0 or < 0
Rational InequalitiesSL & HLSolving inequalities involving rational expressions; critical values and test intervals.Find zeros of numerator and denominator; test intervals; exclude values making denominator zero
Factor TheoremHL OnlyIf (x - a) is a factor of f(x)Then f(a) = 0; used to factorise polynomials.f(a) = 0 implies (x - a) divides f(x); find integer roots among factors of constant term
Remainder TheoremHL OnlyThe remainder when f(x) is divided by (x - a) equals f(a).f(x) = (x - a)Q(x) + f(a); remainder when dividing by (ax - b) is f(b/a)
Rational FunctionsHL OnlyFunctions of the form f(x) = p(x)/q(x); identifying vertical, horizontal, and oblique asymptotes.Vertical asymptotes where q(x) = 0; horizontal asymptote from p(x)/q(x) as x \to \pm\infty
Domain Restriction for InversesHL OnlyRestricting the domain of a non-injective function so that its inverse exists and is also a function.N/A
Self-Inverse FunctionsHL OnlyFunctions for which f = f^{-1}; their graphs are symmetric about y = x.f(f(x)) = x; examples: f(x) = a - x``f(x) = 1/x
Reciprocal Function GraphsHL OnlySketching y = 1/f(x) from the graph of y = f(x); new asymptotes at zeros of f(x).N/A
Absolute Value GraphsHL OnlySketching `y =f(x)
Modulus EquationsHL OnlySolving equations of the form `f(x)
Modulus InequalitiesHL OnlySolving inequalities involving absolute value.`
3. Geometry and TrigonometryDistance in 3D SpaceSL & HLCalculating the distance between two points in three-dimensional space.d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2}
Midpoint in 3D SpaceSL & HLFinding the midpoint of a line segment in 3D.M = ((x_1+x_2)/2, (y_1+y_2)/2, (z_1+z_2)/2)
Volume and Surface AreaSL & HLVolume and surface area of cuboid, cylinder, cone, sphere, hemisphere, and composite solids.V_{\mathrm{cyl}} = \pi r^2 h; V_{\mathrm{cone}} = (1/3)\pi r^2 h; V_{\mathrm{sphere}} = (4/3)\pi r^3; SA_{\mathrm{sphere}} = 4\pi r^2
Right-Angled TrigonometrySL & HLSOH-CAH-TOA; finding unknown sides and angles in right-angled triangles.\sin\theta = \mathrm{opp}/\mathrm{hyp}; \cos\theta = \mathrm{adj}/\mathrm{hyp}; \tan\theta = \mathrm{opp}/\mathrm{adj}
Trigonometric Functions and GraphsSL & HLGraphs of sin, cos, tan; period, amplitude, phase shift, and vertical shift.y = a\sin(b(x - c)) + d; period = `2\pi/
Sine RuleSL & HLFinding unknown sides and angles in any triangle.a/\sin A = b/\sin B = c/\sin C; ambiguous case for SSA
Cosine RuleSL & HLFinding unknown sides and angles; generalised Pythagorean theorem for any triangle.a^2 = b^2 + c^2 - 2bc\cos A; A = \cos^{-1}((b^2 + c^2 - a^2)/(2bc))
Area of a TriangleSL & HLFormula using two sides and the included angle.A = (1/2)ab\sin C
Pythagorean IdentitySL & HLFundamental trigonometric identity relating sin and cos.\sin^2\theta + \cos^2\theta = 1
Double Angle IdentitiesSL & HLExpressions for \sin 2\theta``\cos 2\thetaAnd \tan 2\theta in terms of \sin\theta and \cos\theta.\sin 2\theta = 2\sin\theta\cos\theta; \cos 2\theta = \cos^2\theta - \sin^2\theta = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta
Vectors as Column VectorsSL & HLRepresenting vectors in component form; adding, subtracting, and scalar multiplication.\mathbf{v} = \begin{pmatrix}a \\ b \end{pmatrix}; `\mathbf{v} + \mathbf{w} = \begin`\{pmatrix}` a+c \\ b+d \end`\{pmatrix}
Magnitude of a VectorSL & HLCalculating the length (magnitude) of a vector in 2D and 3D.`
Unit VectorsSL & HLVectors with magnitude 1; expressing a vector as a scalar multiple of a unit vector.`\hat{\mathbf{v}} = \mathbf{v}/
Scalar (Dot) ProductSL & HLDefinition in terms of components and in terms of magnitudes and angle; geometric interpretation as projection.\mathbf{v} \cdot \mathbf{w} = a_1 b_1 + a_2 b_2 (+ a_3 b_3); `\mathbf{v} \cdot \mathbf{w} =
Angle Between Two VectorsSL & HLUsing the scalar product to determine the angle between two vectors.`\cos\theta = (\mathbf{v} \cdot \mathbf{w}) / (
Perpendicularity of VectorsSL & HLTwo vectors are perpendicular if and only if their scalar product is zero.\mathbf{v} \perp \mathbf{w} iff \mathbf{v} \cdot \mathbf{w} = 0
Vector Equation of a LineSL & HLLines in two and three dimensions expressed in vector form with a position vector and direction vector.\mathbf{r} = \mathbf{a} + \lambda\mathbf{b} where \mathbf{a} is on the line, \mathbf{b} is the direction vector
Parametric Line EquationsSL & HLExpressing the coordinates of points on a line in terms of a parameter.x = x_0 + \lambda a``y = y_0 + \lambda b``z = z_0 + \lambda c
Cartesian (Symmetric) Line EquationsSL & HLEliminating the parameter to obtain the symmetric form of a line equation.(x - x_0)/a = (y - y_0)/b = (z - z_0)/c
Cross Product (Vector Product)HL OnlyThe vector product of two vectors in 3D; result is a vector perpendicular to both inputs.\mathbf{v} \times \mathbf{w} computed via determinant of a 3x3 matrix
Properties of the Cross ProductHL OnlyAnti-commutativity; magnitude gives area of parallelogram; scalar triple product gives volume of parallelepiped.\mathbf{v} \times \mathbf{w} = -(\mathbf{w} \times \mathbf{v}); `
Equation of a PlaneHL OnlyCartesian, vector, and parametric forms of a plane in 3D.\mathbf{r} \cdot \mathbf{n} = d; ax + by + cz = d; \mathbf{r} = \mathbf{a} + \lambda\mathbf{b} + \mu\mathbf{c} (parametric)
Intersection of Line and PlaneHL OnlyFinding the point of intersection; determining whether a line is parallel to or lies in a plane.Substitute parametric line equations into plane equation; solve for \lambda
Angle Between Line and PlaneHL OnlyFinding the angle between a line and a plane using the direction vector and the normal vector.`\sin\theta =
Angle Between Two PlanesHL OnlyFinding the angle between two planes using their normal vectors.`\cos\theta =
Complex Numbers on the Argand DiagramHL OnlyRepresenting complex numbers geometrically; the Argand plane with real and imaginary axes.z = a + bi plotted at (a, b); multiplication: add arguments, multiply moduli
Compound Angle IdentitiesHL OnlyFormulae for sine, cosine, and tangent of the sum and difference of two angles.\sin(\alpha \pm \beta) = \sin\alpha\cos\beta \pm \cos\alpha\sin\beta; \cos(\alpha \pm \beta) = \cos\alpha\cos\beta \mp \sin\alpha\sin\beta
Reciprocal Trigonometric FunctionsHL OnlyDefinitions and identities for sec, cosec, and cot.\sec\theta = 1/\cos\theta; \cosec\theta = 1/\sin\theta; \cot\theta = \cos\theta/\sin\theta
Matrix Addition and Scalar MultiplicationHL OnlyAdding and subtracting matrices of the same order; multiplying a matrix by a scalar.(A + B)_{ij}= A_{ij}+ B_{ij}; `(kA)_`\{ij}` = k \cdot A_`\{ij}
Matrix MultiplicationHL OnlyMultiplying matrices; conditions for multiplication; identity matrix.(AB)_{ij}= \sum_k A_{ik}B_{kj}“; AI = IA = A; matrix multiplication is not commutative
Determinants (2x2 and 3x3)HL OnlyCalculating determinants; geometric interpretation as area/volume scale factor.\det\begin{pmatrix}a & b \\ c & d \end{pmatrix}= ad - bc; 3x3 by cofactor expansion
Inverse of a 2x2 MatrixHL OnlyFormula for the inverse of a 2x2 matrix; verifying by multiplication.\begin{pmatrix}a & b \\ c & d \end{pmatrix}^{-1} = \frac{1}{ad-bc}\begin{pmatrix}d & -b \\ -c & a \end{pmatrix}“
Inverse of a 3x3 MatrixHL OnlyFinding the inverse using the adjugate (adjoint) matrix method.A^{-1} = (1/\det A) \cdot \mathrm{adj}(A); A^{-1} exists iff \det A \ne 0
Solving Systems with Inverse MatricesHL OnlySolving A\mathbf{x} = \mathbf{b} by pre-multiplying by A^{-1}.\mathbf{x} = A^{-1}\mathbf{b}; requires \det A \ne 0 (unique solution)
Augmented Matrices and Row ReductionHL OnlySolving systems by Gaussian elimination; row operations on augmented matrices.Row operations: swap rows, multiply row by scalar, add multiple of one row to another
EigenvaluesHL OnlyScalar values \lambda satisfying A\mathbf{v} = \lambda\mathbf{v}; found by solving the characteristic equation.\det(A - \lambda I) = 0; for 2x2: \lambda^2 - \mathrm{tr}(A)\lambda + \det(A) = 0
EigenvectorsHL OnlyNon-zero vectors \mathbf{v} satisfying A\mathbf{v} = \lambda\mathbf{v}; finding for each eigenvalue.Solve (A - \lambda I)\mathbf{v} = \mathbf{0} for each \lambda; eigenvectors are unique up to scalar multiples
4. Statistics and ProbabilityPopulations and SamplesSL & HLDistinguishing between populations (entire group) and samples (subset); representative sampling.N/A
Sampling MethodsSL & HLSimple random, systematic, stratified, and quota sampling; convenience, judgement, and voluntary response.N/A
Reliability and BiasSL & HLIdentifying sources of bias; understanding the effect of sample size on reliability.N/A
Measures of Central TendencySL & HLMean, median, and mode; their relative merits for different data types (discrete vs continuous, skewed data).\bar{x} = \sum x_i / n; median = middle value; mode = most frequent value
Grouped DataSL & HLEstimating the mean from grouped data using mid-interval values.\bar{x} \approx \sum(f_i x_i) / \sum f_i where x_i is the midpoint of class i
Variance and Standard DeviationSL & HLMeasuring the spread of data around the mean; using the unbiased estimator for sample variance.s^2 = \sum(x_i - \bar{x})^2 / (n-1); s = \sqrt{s^2}; IQR = Q_3 - Q_1
HistogramsSL & HLFrequency histograms with equal and unequal class widths; frequency density.Frequency density = frequency / class width; area of bar = frequency
Box-and-Whisker PlotsSL & HLFive-number summary (min, Q1, median, Q3, max); identifying outliers and comparing distributions.Outlier: value < Q_1 - 1.5 \times IQR or > Q_3 + 1.5 \times IQR
Cumulative Frequency GraphsSL & HLConstructing ogives; estimating median, quartiles, and percentiles from the graph.N/A
Set Theory and NotationSL & HLUniversal set, subsets, union, intersection, complement; two-set and three-set Venn diagrams.P(A \cup B) = P(A) + P(B) - P(A \cap B); P(A') = 1 - P(A)
Conditional ProbabilitySL & HLThe probability of an event given that another event has occurred; restricted sample space.`P(A
Independence of EventsSL & HLTwo events are independent if the occurrence of one does not affect the probability of the other.A \perp B iff P(A \cap B) = P(A)P(B) iff `P(A
Tree Diagrams and Sample SpacesSL & HLUsing tree diagrams for sequential events; exhaustive sample spaces for equally likely outcomes.N/A
Discrete Random VariablesSL & HLRandom variables that take countable values; probability mass functions (PMF).Conditions: 0 \le p(x) \le 1 for all x; \sum p(x) = 1
Expected ValueSL & HLThe long-run average value of a discrete random variable.E(X) = \sum x_i p(x_i); linearity: E(aX + b) = aE(X) + b
Variance of a Discrete Random VariableSL & HLMeasuring the spread of a discrete random variable about its mean.Var(X) = E(X^2) - [E(X)]^2; Var(aX + b) = a^2 Var(X)
Binomial DistributionSL & HLModelling the number of successes in n independent Bernoulli trials with probability p.X \sim B(n, p); P(X = x) = \binom{n}{x}p^x(1-p)^{n-x}; E(X) = np; Var(X) = np(1-p)
Normal DistributionSL & HLProperties of the normal curve; symmetric about \mu; approximately 68-95-99.7 rule; standardisation.X \sim N(\mu, \sigma^2); Z = (X - \mu)/\sigma where Z \sim N(0, 1)
Standard Normal DistributionSL & HLThe standard normal Z; using tables or technology to find probabilities.P(Z < z) from tables; P(a < Z < b) = P(Z < b) - P(Z < a)
Linear Regression: Equation of LineSL & HLEquation of the least squares regression line of y on x; interpreting slope and y-intercept.y - \bar{y} = r(s_y/s_x)(x - \bar{x}); y = a + bx where b = r(s_y/s_x)
Pearson’s Correlation CoefficientSL & HLMeasuring the strength and direction of linear association; interpreting r and r^2.r = \frac{\sum(x_i - \bar{x})(y_i - \bar{y})}{\sqrt{\sum(x_i-\bar{x})^2 \sum(y_i-\bar{y})^2}}; -1 \le r \le 1
Bayes’ TheoremHL OnlyReversing conditional probabilities; partitioning the sample space using the law of total probability.`P(A
Poisson DistributionHL OnlyModelling the number of rare events in a fixed interval; Poisson as a limit of the binomial.X \sim Po(\lambda); P(X = x) = e^{-\lambda}\lambda^x / x!; E(X) = Var(X) = \lambda
Probability Density FunctionsHL OnlyContinuous analogue of a PMF; f(x) \ge 0 and total area under the curve equals 1.P(a \le X \le b) = \int_a^b f(x)\,dx; \int_{-\infty}^{\infty} f(x)\,dx = 1
Cumulative Distribution FunctionsHL OnlyF(x) = P(X \le x); the CDF is the integral of the PDF; F'(x) = f(x).F(x) = \int_{-\infty}^x f(t)\,dt; P(a < X < b) = F(b) - F(a)
Expected Value (Continuous)HL OnlyThe mean of a continuous random variable; calculated by integration.E(X) = \int_{-\infty}^{\infty} xf(x)\,dx; E(X^2) = \int_{-\infty}^{\infty} x^2 f(x)\,dx
Variance (Continuous)HL OnlyThe variance of a continuous random variable.Var(X) = E(X^2) - [E(X)]^2
Median, Mode, Quartiles (Continuous)HL OnlyFinding the median, mode, and quartiles for continuous distributions.Median: solve F(m) = 0.5; Q_1: solve F(q) = 0.25; Q_3: solve F(q) = 0.75
Linear Transformation of a VariableHL OnlyEffect of Y = aX + b on mean, variance, and standard deviation.E(Y) = aE(X) + b; Var(Y) = a^2 Var(X); `\sigma_Y =
Linear Combinations of Independent VariablesHL OnlyMean and variance of sums and differences of independent random variables.E(aX + bY) = aE(X) + bE(Y); Var(aX + bY) = a^2 Var(X) + b^2 Var(Y) for independent X, Y
Inverse Normal DistributionHL OnlyGiven a probability, finding the corresponding value of X.X = \mu + Z\sigma where Z is found from the inverse normal function
Student’s t-DistributionHL OnlyUsed when population standard deviation is unknown and sample size is small; degrees of freedom = n - 1.CI for \mu: \bar{x} \pm t_{n-1,\alpha/2} \cdot s/\sqrt{n}
Hypothesis Testing: ConceptsHL OnlyNull and alternative hypotheses; significance level \alpha; p-values; Type I and Type II errors.H_0 vs H_1; reject H_0 if p-value < \alpha
Chi-Squared Test for IndependenceHL OnlyTesting whether two categorical variables are independent; observed vs expected frequencies.\chi^2 = \sum (O_i - E_i)^2 / E_i; E_i = (\mathrm{row total} \times \mathrm{col total}) / \mathrm{grand total}
Chi-Squared Goodness of FitHL OnlyTesting whether observed data fits a specified theoretical distribution.Same formula; df = (k - 1 - p) where k = categories, p = estimated parameters
5. CalculusInformal Understanding of LimitsSL & HLThe concept of a limit; understanding behaviour as x approaches a value or infinity; one-sided limits.\lim_{x \to a} f(x) = L; \lim_{x \to a^+} vs \lim_{x \to a^-}
ContinuitySL & HLA function is continuous at a point if the limit equals the function value; identifying discontinuities.f is continuous at c if \lim_{x \to c} f(x) = f(c); types: removable, jump, infinite
Differentiation: Power RuleSL & HLThe derivative of x^n; differentiating sums, differences, and constant multiples.f(x) = x^n \implies f'(x) = nx^{n-1}; derivative of a constant is 0
Derivatives of Exponential FunctionsSL & HLDifferentiating e^x and a^x.d/dx(e^x) = e^x; d/dx(a^x) = a^x \ln a; d/dx(e^{f(x)}) = f'(x)e^{f(x)}
Derivatives of Logarithmic FunctionsSL & HLDifferentiating \ln x and \log_a x.d/dx(\ln x) = 1/x; d/dx(\ln f(x)) = f'(x)/f(x)
Derivative of Trigonometric FunctionsSL & HLDifferentiating \sin x``\cos xAnd \tan x (angles in radians).d/dx(\sin x) = \cos x; d/dx(\cos x) = -\sin x; d/dx(\tan x) = \sec^2 x
Product RuleSL & HLDifferentiating the product of two functions.(uv)' = u'v + uv'
Quotient RuleSL & HLDifferentiating the quotient of two functions.(u/v)' = (u'v - uv') / v^2
Chain RuleSL & HLDifferentiating composite functions.dy/dx = (dy/du)(du/dx); d/dx[f(g(x))] = f'(g(x)) \cdot g'(x)
First Derivative TestSL & HLUsing the sign of f'(x) to classify stationary points as local maxima or minima.f'(x) changes + to -: local max; - to +: local min; no change: point of inflection
Second DerivativeSL & HLFinding f''(x); using it to determine concavity and points of inflection.f''(x) = d/dx[f'(x)]; f''(x) > 0: concave up; f''(x) < 0: concave down
Equation of a TangentSL & HLFinding the gradient at a point and writing the equation of the tangent line.y - y_0 = f'(x_0)(x - x_0); gradient = f'(x_0)
Equation of a NormalSL & HLThe normal is perpendicular to the tangent; gradient is the negative reciprocal.y - y_0 = -(1/f'(x_0))(x - x_0); condition: f'(x_0) \ne 0
Points of InflectionSL & HLPoints where the concavity changes; second derivative changes sign.f''(x_0) = 0 and f''(x) changes sign at x_0
OptimisationSL & HLFormulating and solving real-world problems involving maxima and minima.Find f'(x) = 0Classify critical points, check endpoints if domain is restricted
Indefinite IntegrationSL & HLAntidifferentiation; the constant of integration C.\int x^n\,dx = x^{n+1}/(n+1) + C for n \ne -1; `\int 1/x,dx = \ln
Definite IntegrationSL & HLEvaluating the definite integral using the Fundamental Theorem of Calculus.\int_a^b f(x)\,dx = [F(x)]_a^b = F(b) - F(a)
Area Under a CurveSL & HLUsing definite integration to find the area between a curve and the x-axis.A = \int_a^b f(x)\,dx when f(x) \ge 0; split at roots where f(x) changes sign
Area Between Two CurvesSL & HLFinding the enclosed area between two functions over a given interval.A = \int_a^b [f(x) - g(x)]\,dx where f(x) \ge g(x) on [a, b]
Trapezoidal RuleSL & HLNumerical approximation of a definite integral; accuracy increases with more trapezia.\int_a^b f(x)\,dx \approx (h/2)[y_0 + 2y_1 + 2y_2 + \cdots + 2y_{n-1} + y_n] where h = (b-a)/n
Kinematics: Displacement and VelocitySL & HLDisplacement, velocity, and acceleration as functions of time.v = ds/dt; a = dv/dt = d^2s/dt^2; s = \int v\,dt; v = \int a\,dt
Kinematics: Total Distance TravelledSL & HLFinding total distance travelled from a velocity-time graph.Total distance = `\int_a^b
Implicit DifferentiationHL OnlyDifferentiating equations where y is defined implicitly as a function of x.d/dx[y^n] = ny^{n-1}\,dy/dx; d/dx[xy] = y + x\,dy/dx
Related Rates of ChangeHL OnlyConnecting the rates of change of related quantities using the chain rule.dy/dt = (dy/dx)(dx/dt); differentiate both sides of a relation with respect to t
Integration by SubstitutionHL OnlyUsing a substitution to simplify integrals; changing limits for definite integrals.\int f(g(x))g'(x)\,dx = \int f(u)\,du where u = g(x)``du = g'(x)\,dx
Integration by PartsHL OnlyReversing the product rule; choosing u and dv strategically using LIATE.\int u\,dv = uv - \int v\,du; repeated application when necessary
Definite Integrals Using TechnologyHL OnlyEvaluating definite integrals numerically using a graphing calculator (GDC).N/A
Volumes of Revolution about the x-AxisHL OnlyVolume generated by rotating a region about the x-axis.V_x = \pi\int_a^b [f(x)]^2\,dx
Volumes of Revolution about the y-AxisHL OnlyVolume generated by rotating a region about the y-axis.V_y = \pi\int_c^d [g(y)]^2\,dy
Separable Differential EquationsHL OnlyFirst-order ODEs of the form dy/dx = f(x)g(y); separating variables and integrating.\int dy/g(y) = \int f(x)\,dx + C; verify solution by substitution
Maclaurin Series: ConceptHL OnlyExpressing f(x) as an infinite polynomial series about x = 0; interval of convergence.f(x) = \sum_{n=0}^{\infty} f^{(n)}(0)\,x^n / n!
Common Maclaurin SeriesHL OnlyStandard Maclaurin series for e^x``\sin x``\cos x``\ln(1+x)``(1+x)^n.e^x = 1 + x + x^2/2! + x^3/3! + \cdots; \sin x = x - x^3/3! + x^5/5! - \cdots
Integration by Partial FractionsHL OnlyDecomposing proper rational functions into partial fractions before integrating.P(x)/Q(x) = A/(x-a) + B/(x-b) + \cdots; each term integrates to a log or power
L’Hopital’s RuleHL OnlyEvaluating limits of indeterminate forms by differentiating numerator and denominator.\lim_{x \to a} f(x)/g(x) = \lim_{x \to a} f'(x)/g'(x) for 0/0 or \infty/\infty forms
Improper Integrals: Infinite LimitsHL OnlyIntegrals where one or both limits are infinite; determining convergence or divergence.\int_a^{\infty} f(x)\,dx = \lim_{b \to \infty} \int_a^b f(x)\,dx; converges if the limit is finite
Improper Integrals: Unbounded IntegrandsHL OnlyIntegrals where the integrand has a vertical asymptote within the interval.\int_0^1 (1/\sqrt{x})\,dx = \lim_{a \to 0^+} \int_a^1 (1/\sqrt{x})\,dx = 2; split at the discontinuity
Convergence of Improper IntegralsHL OnlyDetermining whether an improper integral converges to a finite value or diverges.\int_1^{\infty} (1/x^p)\,dx converges for p > 1Diverges for p \le 1

Worked Example: Arithmetic and Geometric Series (Topic 1)

Section titled “Worked Example: Arithmetic and Geometric Series (Topic 1)”

An arithmetic sequence has first term 5 and common difference 3. A geometric sequence has first term 2 and common ratio 2. Find the smallest value of nn such that the sum of the first nn terms of the geometric sequence exceeds the sum of the first nn terms of the arithmetic sequence.

Solution
  • Arithmetic sum: Sn=n2(2(5)+(n−1)(3))=n2(10+3n−3)=n(3n+7)2S_n = \dfrac{n}{2}(2(5) + (n-1)(3)) = \dfrac{n}{2}(10 + 3n - 3) = \dfrac{n(3n + 7)}{2}
  • Geometric sum: Tn=2(2n−1)2−1=2(2n−1)=2n+1−2T_n = \dfrac{2(2^n - 1)}{2 - 1} = 2(2^n - 1) = 2^{n+1} - 2
  • We need 2n+1−2>n(3n+7)22^{n+1} - 2 \gt \dfrac{n(3n + 7)}{2}.
  • Testing values:
  • n=4n = 4: geometric =30= 30 Arithmetic =4(19)2=38= \dfrac{4(19)}{2} = 38. Geometric is smaller.
  • n=5n = 5: geometric =62= 62 Arithmetic =5(22)2=55= \dfrac{5(22)}{2} = 55. Geometric exceeds arithmetic.
  • Answer: n=5n = 5

Worked Example: Binomial Expansion (Topic 1)

Section titled “Worked Example: Binomial Expansion (Topic 1)”

Expand (1+2x)5(1 + 2x)^5 in ascending powers of xx up to and including the term in x3x^3.

Solution
  • Using the binomial theorem with a = 1$$b = 2x$$n = 5:
  • (1+2x)5=1+5(2x)+10(2x)2+10(2x)3+⋯(1 + 2x)^5 = 1 + 5(2x) + 10(2x)^2 + 10(2x)^3 + \cdots
  • =1+10x+40x2+80x3+⋯= 1 + 10x + 40x^2 + 80x^3 + \cdots

Worked Example: Transformations of Functions (Topic 2)

Section titled “Worked Example: Transformations of Functions (Topic 2)”

The graph of y=f(x)y = f(x) passes through the point (3,5)(3, 5). Find the coordinates of the corresponding Point on the graph of y=−2f(x−1)+3y = -2f(x - 1) + 3.

Solution
  • Apply transformations step by step:
  1. f(x)→f(x−1)f(x) \to f(x - 1): translate right by 1: (3,5)→(4,5)(3, 5) \to (4, 5)
  2. →2f(x−1)\to 2f(x - 1): vertical stretch by factor 2: (4,5)→(4,10)(4, 5) \to (4, 10)
  3. →−2f(x−1)\to -2f(x - 1): reflect in xx-axis: (4,10)→(4,−10)(4, 10) \to (4, -10)
  4. →−2f(x−1)+3\to -2f(x - 1) + 3: translate up by 3: (4,−10)→(4,−7)(4, -10) \to (4, -7)
  • Answer: (4,−7)(4, -7)

Worked Example: Quadratic Inequalities (Topic 2)

Section titled “Worked Example: Quadratic Inequalities (Topic 2)”

Solve the inequality x2−5x+6<0x^2 - 5x + 6 \lt 0.

Solution
  • Factorise: x2−5x+6=(x−2)(x−3)x^2 - 5x + 6 = (x - 2)(x - 3)
  • The parabola opens upward (positive x2x^2 coefficient) with roots at x=2x = 2 and x=3x = 3.
  • The expression is negative between the roots: 2<x<32 \lt x \lt 3

Worked Example: Trigonometric Equations (Topic 3)

Section titled “Worked Example: Trigonometric Equations (Topic 3)”

Solve cos⁡2x=cos⁡x\cos 2x = \cos x for 0≤x≤π0 \le x \le \pi.

Solution
  • Using cos⁡2x=2cos⁡2x−1\cos 2x = 2\cos^2 x - 1:
  • 2cos⁡2x−1=cos⁡x  ⟹  2cos⁡2x−cos⁡x−1=02\cos^2 x - 1 = \cos x \implies 2\cos^2 x - \cos x - 1 = 0
  • Let u=cos⁡xu = \cos x: 2u2−u−1=0  ⟹  (2u+1)(u−1)=02u^2 - u - 1 = 0 \implies (2u + 1)(u - 1) = 0
  • u=−1/2u = -1/2 or u=1u = 1
  • cos⁡x=−1/2  ⟹  x=2π/3\cos x = -1/2 \implies x = 2\pi/3 (only solution in [0,π][0, \pi])
  • cos⁡x=1  ⟹  x=0\cos x = 1 \implies x = 0
  • Solutions: x=0,2π/3x = 0, 2\pi/3

Worked Example: Vector Line Intersection (Topic 3, HL)

Section titled “Worked Example: Vector Line Intersection (Topic 3, HL)”

Find the point of intersection of the lines r1=(120)+λ(2−13)\mathbf{r}_1 = \begin{pmatrix} 1 \\ 2 \\ 0 \end{pmatrix} + \lambda\begin{pmatrix} 2 \\ -1 \\ 3 \end{pmatrix} and r2=(301)+μ(11−1)\mathbf{r}_2 = \begin{pmatrix} 3 \\ 0 \\ 1 \end{pmatrix} + \mu\begin{pmatrix} 1 \\ 1 \\ -1 \end{pmatrix}.

Solution
  • Equate components:
  • 1+2λ=3+μ1 + 2\lambda = 3 + \mu … (i)
  • 2−λ=μ2 - \lambda = \mu … (ii)
  • 3λ=1−μ3\lambda = 1 - \mu … (iii)
  • From (i) and (ii): 1+2λ=3+2−λ  ⟹  3λ=4  ⟹  λ=4/31 + 2\lambda = 3 + 2 - \lambda \implies 3\lambda = 4 \implies \lambda = 4/3
  • From (ii): μ=2−4/3=2/3\mu = 2 - 4/3 = 2/3
  • Verify with (iii): 3(4/3)=43(4/3) = 4 and 1−2/3=1/31 - 2/3 = 1/3. These do not match, so the lines are skew (they do not intersect).

If you get this wrong, revise: Vector equations of lines and intersection conditions (Topic 3).

Worked Example: Probability with Venn Diagrams (Topic 4)

Section titled “Worked Example: Probability with Venn Diagrams (Topic 4)”

In a survey, 60 people were asked whether they liked tea (TT) and coffee (CC). 35 liked tea, 40 Liked coffee, and 15 liked both. Find the probability that a randomly chosen person liked neither.

Solution
  • n(T∪C)=n(T)+n(C)−n(T∩C)=35+40−15=60n(T \cup C) = n(T) + n(C) - n(T \cap C) = 35 + 40 - 15 = 60
  • Everyone liked at least one, so n((T∪C)′)=0n((T \cup C)') = 0.
  • P(neither)=0/60=0P(\mathrm{neither}) = 0/60 = 0

Worked Example: Normal Distribution (Topic 4)

Section titled “Worked Example: Normal Distribution (Topic 4)”

Heights of a population are normally distributed with mean 170170 cm and standard deviation 88 cm. Find The probability that a randomly selected person is between 162162 cm and 178178 cm tall.

Solution
  • Standardise:
  • z1=(162−170)/8=−1.00z_1 = (162 - 170)/8 = -1.00
  • z2=(178−170)/8=1.00z_2 = (178 - 170)/8 = 1.00
  • P(162<X<178)=P(−1<Z<1)=Φ(1)−Φ(−1)=0.8413−0.1587=0.6826P(162 \lt X \lt 178) = P(-1 \lt Z \lt 1) = \Phi(1) - \Phi(-1) = 0.8413 - 0.1587 = 0.6826

Worked Example: Differentiation — Quotient Rule (Topic 5)

Section titled “Worked Example: Differentiation — Quotient Rule (Topic 5)”

Find the equation of the normal to the curve y=x2+1x−1y = \dfrac{x^2 + 1}{x - 1} at the point where x=2x = 2.

Solution
  • Quotient rule: u = x^2 + 1$$v = x - 1. Then u' = 2x$$v' = 1.
  • dydx=2x(x−1)−(x2+1)(x−1)2=2x2−2x−x2−1(x−1)2=x2−2x−1(x−1)2\dfrac{dy}{dx} = \dfrac{2x(x - 1) - (x^2 + 1)}{(x - 1)^2} = \dfrac{2x^2 - 2x - x^2 - 1}{(x - 1)^2} = \dfrac{x^2 - 2x - 1}{(x - 1)^2}
  • At x=2x = 2: dydx=4−4−11=−1\dfrac{dy}{dx} = \dfrac{4 - 4 - 1}{1} = -1
  • Point: y(2)=(4+1)/(2−1)=5y(2) = (4 + 1)/(2 - 1) = 5 So the point is (2,5)(2, 5).
  • Normal gradient: mnormal=1m_{\mathrm{normal}} = 1 (negative reciprocal of −1-1).
  • Normal equation: y−5=1(x−2)  ⟹  y=x+3y - 5 = 1(x - 2) \implies y = x + 3

Worked Example: Volume of Revolution (Topic 5, HL)

Section titled “Worked Example: Volume of Revolution (Topic 5, HL)”

Find the volume generated when the region bounded by y=xy = \sqrt{x} The xx-axis, and x=4x = 4 is rotated 360360 degrees about the xx-axis.

Solution
  • V=π∫04(x)2 dx=π∫04x dx=π[x22]04=π×8=8πV = \pi\displaystyle\int_0^4 (\sqrt{x})^2\,dx = \pi\displaystyle\int_0^4 x\,dx = \pi\left[\dfrac{x^2}{2}\right]_0^4 = \pi \times 8 = 8\pi

The SL course covers Topics 1-5 at a foundational level. Students are expected to understand and apply core concepts in number and algebra, functions, geometry and trigonometry, statistics and probability, and calculus. Internal assessment (IA) counts for 20% of the final grade, and the remaining 80% is assessed through two written examination papers (Paper 1: non-calculator, Paper 2: Calculator).

The HL course extends the SL content with additional subtopics in all five areas. HL students sit Two additional papers (Paper 3: problem-solving with extended response questions) and cover more advanced techniques including complex numbers, matrices, further calculus, and hypothesis testing. The HL course demands deeper conceptual understanding and greater fluency with algebraic Manipulation.


  • Number and Algebra — arithmetic and geometric sequences, sigma notation, binomial theorem
  • Complex Numbers — complex numbers in Cartesian, polar, and Euler form; De Moivre’s theorem; roots of polynomials
  • Trigonometry — trigonometric functions, identities, sine and cosine rules
  • Vectors — vector operations, scalar and cross products, lines and planes
  • Integration — antiderivatives, definite integration, area, integration techniques
  • Logic (Discrete Maths) — propositional logic, truth tables, proof
  • Maths Index — overview of all mathematics notes

  1. Find the sum of the infinite geometric series 8+4+2+1+⋯8 + 4 + 2 + 1 + \cdots
Solution
  • u_1 = 8$$r = 4/8 = 0.5. Since ∣r∣<1|r| \lt 1 The sum converges.
  • S∞=81−0.5=16S_\infty = \dfrac{8}{1 - 0.5} = 16

If you get this wrong, revise: Sum to infinity of geometric series (Topic 1).

  1. Find the coefficient of x4x^4 in the expansion of (1−3x)8(1 - 3x)^8.
Solution
  • General term: (8r)(−3x)r\dbinom{8}{r}(-3x)^r. For x4x^4 Need r=4r = 4.
  • (84)(−3)4=70×81=5670\dbinom{8}{4}(-3)^4 = 70 \times 81 = 5670

If you get this wrong, revise: Binomial theorem, finding specific coefficients (Topic 1).

  1. The function f(x)=2x3−3x2−12x+5f(x) = 2x^3 - 3x^2 - 12x + 5 has a local maximum and a local minimum. Find the coordinates of both.
Solution
  • f′(x)=6x2−6x−12=6(x2−x−2)=6(x−2)(x+1)f'(x) = 6x^2 - 6x - 12 = 6(x^2 - x - 2) = 6(x - 2)(x + 1)
  • Stationary points at x=2x = 2 and x=−1x = -1.
  • f′′(x)=12x−6f''(x) = 12x - 6
  • At x=−1x = -1: f′′(−1)=−18<0f''(-1) = -18 \lt 0 (local max). f(−1)=−2−3+12+5=12f(-1) = -2 - 3 + 12 + 5 = 12. Point: (−1,12)(-1, 12).
  • At x=2x = 2: f′′(2)=18>0f''(2) = 18 \gt 0 (local min). f(2)=16−12−24+5=−15f(2) = 16 - 12 - 24 + 5 = -15. Point: (2,−15)(2, -15).

If you get this wrong, revise: First and second derivative tests (Topic 5).

  1. Find the inverse of f(x)=3x+2x−1f(x) = \dfrac{3x + 2}{x - 1} and state its domain.
Solution
  • Let y=3x+2x−1y = \dfrac{3x + 2}{x - 1}. Swap: x=3y+2y−1x = \dfrac{3y + 2}{y - 1}.
  • x(y−1)=3y+2  ⟹  xy−x=3y+2  ⟹  xy−3y=x+2x(y - 1) = 3y + 2 \implies xy - x = 3y + 2 \implies xy - 3y = x + 2
  • y(x−3)=x+2  ⟹  f−1(x)=x+2x−3y(x - 3) = x + 2 \implies f^{-1}(x) = \dfrac{x + 2}{x - 3}
  • Domain of f−1f^{-1}: x≠3x \neq 3 (i.e. R∖3\mathbb{R} \setminus \\{3\\}).

If you get this wrong, revise: Finding inverse functions and domain restrictions (Topic 2).

  1. Triangle ABCABC has sides a = 9$$b = 7$$c = 5. Find the largest angle.
Solution
  • The largest angle is opposite the longest side, so angle AA:
  • cos⁡A=b2+c2−a22bc=49+25−8170=−770=−0.1\cos A = \dfrac{b^2 + c^2 - a^2}{2bc} = \dfrac{49 + 25 - 81}{70} = \dfrac{-7}{70} = -0.1
  • A=arccos⁡(−0.1)=95.7A = \arccos(-0.1) = 95.7 degrees

If you get this wrong, revise: Cosine rule for finding an angle (Topic 3).

  1. Find the area of a triangle with sides 66 cm and 88 cm and an included angle of 5050 degrees.
Solution
  • A=12absin⁡C=12(6)(8)sin⁡50∘=24×0.7660=18.4A = \dfrac{1}{2}ab\sin C = \dfrac{1}{2}(6)(8)\sin 50^\circ = 24 \times 0.7660 = 18.4 cm2^2

If you get this wrong, revise: Area of a triangle formula A=12absin⁡CA = \frac{1}{2}ab\sin C (Topic 3).

  1. A bag contains 4 red and 6 blue marbles. Three marbles are drawn without replacement. Find the probability that exactly two are red.
Solution
  • Total ways to choose 3 from 10: (103)=120\dbinom{10}{3} = 120
  • Ways to choose 2 red from 4 and 1 blue from 6: (42)×(61)=6×6=36\dbinom{4}{2} \times \dbinom{6}{1} = 6 \times 6 = 36
  • P=36/120=3/10=0.3P = 36/120 = 3/10 = 0.3

If you get this wrong, revise: Combinations and probability (Topics 1, 4).

  1. Scores on a test are normally distributed with μ=65\mu = 65 and σ=10\sigma = 10. The top 10% of students receive an A grade. Find the minimum score for an A.
Solution
  • We need the 90th percentile: P(X<c)=0.90P(X \lt c) = 0.90
  • P(Z<z)=0.90  ⟹  z=1.282P(Z \lt z) = 0.90 \implies z = 1.282
  • c=μ+zσ=65+1.282×10=65+12.82=77.8c = \mu + z\sigma = 65 + 1.282 \times 10 = 65 + 12.82 = 77.8
  • Minimum score for an A: 7878 (rounding up).

If you get this wrong, revise: Inverse normal distribution and percentiles (Topic 4).

  1. Find ∫0π/2sin⁡xcos⁡x dx\displaystyle\int_0^{\pi/2} \sin x \cos x\,dx.
Solution
  • Let u = \sin x$$du = \cos x\,dx:
  • ∫0π/2u du=[u22]0π/2=[sin⁡2x2]0π/2=12−0=12\displaystyle\int_0^{\pi/2} u\,du = \left[\dfrac{u^2}{2}\right]_0^{\pi/2} = \left[\dfrac{\sin^2 x}{2}\right]_0^{\pi/2} = \dfrac{1}{2} - 0 = \dfrac{1}{2}

If you get this wrong, revise: Integration by substitution (Topic 5).

  1. Find the equation of the tangent to y=ln⁡(x2+1)y = \ln(x^2 + 1) at x=1x = 1.
Solution
  • dydx=2xx2+1\dfrac{dy}{dx} = \dfrac{2x}{x^2 + 1} (chain rule)
  • At x=1x = 1: gradient =2/2=1= 2/2 = 1; y=ln⁡2y = \ln 2
  • Tangent: y−ln⁡2=1(x−1)  ⟹  y=x−1+ln⁡2y - \ln 2 = 1(x - 1) \implies y = x - 1 + \ln 2

If you get this wrong, revise: Chain rule and equation of a tangent (Topic 5).

  1. Evaluate ∫1eln⁡xx dx\displaystyle\int_1^e \dfrac{\ln x}{x}\,dx.
Solution
  • Substitution: let u = \ln x$$du = dx/x.
  • When x = 1$$u = 0; when x = e$$u = 1.
  • ∫01u du=[u22]01=12\displaystyle\int_0^1 u\,du = \left[\dfrac{u^2}{2}\right]_0^1 = \dfrac{1}{2}

If you get this wrong, revise: Integration by substitution (Topic 5).

  1. Solve the differential equation dydx=xy\dfrac{dy}{dx} = \dfrac{x}{y} given that y=2y = 2 when x=1x = 1.
Solution
  • Separate variables: y dy=x dxy\,dy = x\,dx
  • Integrate: y22=x22+C\dfrac{y^2}{2} = \dfrac{x^2}{2} + C
  • Apply initial condition: 4/2=1/2+C  ⟹  C=3/24/2 = 1/2 + C \implies C = 3/2
  • y2=x2+3y^2 = x^2 + 3
  • Since y=2>0y = 2 \gt 0 at x=1x = 1: y=x2+3y = \sqrt{x^2 + 3}

If you get this wrong, revise: Separable differential equations (HL, Topic 5).

  1. Misreading the question, particularly with ‘hence’ vs ‘hence or otherwise’. The former requires using previous work.

  2. Cancelling terms instead of factors, ab+aca\frac{ab + ac}{a} simplifies to b+cb + c, not bcbc.